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Answer:
1 . In given figure , PQ=RS and ∠ORS=48
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In given figure O is the center of circle and point P,Q,R and S on the circumference of circle
Then line OP, OQ ,OR and OS are the radius of circle
So OP=OQ=OR=OS
In ΔOPQ and ΔORS
PQ=RS (Given )
OP=OR (Radius of circle)
OQ=OS (Radius of circle)
∴ΔPOQ≅ΔORS
∠ORS=∠OPQ=48
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Given ∠ORS=48
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OR=OS (radius)
∴∠OSR=∠ORS=48
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Given\angle ORS=48^{0}$$
In ΔORS
∠ROS+∠ORS+∠OSR=180
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⇒∠ROS+48+48=180
⇒∠ROS=180−48−48=84
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∠OPQ=48
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,∠ROS=84
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