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Answer:
Given
∠E = ∠F = 90°
BF = CF [Equal altitudes of triangle]
To Prove
∠B = ∠C
Proof
In △BFC and △CEB
BE = CF [ Given ]
BC = BC [ Common ]
∠BFC = ∠BEC [ each equal to 90° ]
So, △BFC ≅ △CEB [ By RHS congruence rule ]
∠B = ∠C [ by CPCT ]
Hence Proved ∠B = ∠C