please solve don't spam
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Answer:
refer attachment!!!!!!
Step-by-step explanation:
[tex] {5}^{2x + 1} \div25 = 125 \\ {5}^{2x + 1} \div {5}^{2} = {5}^{3} \\ {5}^{2x + 1 - 2} = {5}^{3} \\ {5}^{2x - 1} = {5}^{3} \\ \\ 2x - 1 = 3 \\ 2x = 3 + 1 = 4 \\ x = \frac{4}{2} \\ x = 2[/tex]
[tex]{5}^{2x + 1} \div {5}^{2} = {5}^{3} \\ = 2x + 1 = 2 + 3 \\ = 2x + 1 = 5 \\ = 2x = 5 - 1 \\ = 2x = 4 \\ = x = \frac{4}{2} \\ = x = 2[/tex]