Please solve. I have exam tomorrow. Please i beg of you
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Please solve. I have exam tomorrow. Please i beg of you
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Answer:
WE PROVE ANGLE A BISECT BC
SO,
IN ΔABD = ACD
==> AD = AD (COMMON)
==> ∠ADB = ∠ADC (EACH 90°)
AB = AC (GIVEN)
BY SAS CONGRUENCE RULE
ΔABD = ΔACD
SO, BY CPCT
∠BAD = ∠BAC
SO, ∠A BISECT BC