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Answer:
Quantity of lead in 50 kg of alloy = 60% of 50 kg = (50 × 60 )kg = 30 kg.
100
Let the required quantity of lead to be added be x kg.
Then, weight of lead = (30 + x) kg.
And, weight of new alloy = (50 + x) kg.
Percentage of lead in new alloy = (30+x) %
( 50+x)
∴ 30+x ×100=75
50+x
⇒ 30+x =3
50+x 4
⇒ 4(30 + x) = 3(50 + x)
⇒ 120 + 4x = 150 + 3x
⇒ 4x - 3x = 150 - 120
⇒ x = 30