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Correct answer will be brainlist
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Answer:
48
Step-by-step explanation:
[tex]\frac{(A+B+C)}{3}[/tex]=33
30+B+C=33 x 3
30+ B+C=99
B+C = 99-30
B+C=63
Now,
[tex]\frac{(B+C+D)}{3}[/tex]=37
B+C+D=111
Substituting B+C
63+D=111
D=48
D obtained 48 marks
Verified answer
BY USING AVERAGE FORMULA
A + B + C / 3 = 33
A +B + C = 99 [A=30]
B+C = 69----(1)
IN SECOND PART
B+C+D / 3 = 37
USING EQ1
69 + D = 111
D= 111 - 69
D = 42
MARK ME AS BRAINLIEST BRO