Please solve this do not spam it will be reported
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Please solve this do not spam it will be reported
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Answer:
b²-4ac
x²+4x-1
4²-4×1×(-1)
16+4=20
D=20
x=-b±√D/2a.
x=-4+2√5/2 |. x=-4-2√5/2
x=-2+2√5,-2-2√5
Answer:
for QE, x^2 + 4x- 1 = 0
D = b^2 - 4ac = (4)^2 - 4(1)(-1)
= 16 + 4 = 20
Thus,
-b ± rootD/ 2a
= -4 ± root20/ 2×1
= -4 + 4root5/ 2 OR
- 4 - 4root5/ 2
= - 1 ± root5 would be your first answer.
Similarly,you will get the root of other two equations.
Hope it helps you.
please mark my answer as brainliest.