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area of a quadrilateral = area of ∆ABC + area of ∆PQD
=> [(6×8)]+[(10×8)] sq cm
=> [48+80] sq cm
=> 128 sq cm
hope it helps please mark me as brainiest
Step-by-step explanation:
area of a quadrilateral = area of ∆ABC + area of ∆PQD
=> [(6×8)]+[(10×8)] sq cm
=> [48+80] sq cm
=> 128 sq cm
area of angle abc + area of angle pqd = 6 times 8 + 10 times 8 = 48 + 80 = 128 area of angle abc+area of angle pqd=6×8+10×8=48+80=128
hope it helps please mark me as brainiest