Please solve this. Please don’t give silly answers.
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Answer:
HOPE THESE BRING A SMILE IN YOUR FACE
Step-by-step explanation:
Answer:
i)[tex]x^2-\left(\frac{3}{2}+\frac{3}{2}\right)x+\frac{9}{4}[/tex] (same zeroes)
=[tex]x^2-\left(3\right)x+\frac{9}{4}\\[/tex]
ii)[tex]x^2-\left(\sqrt{6}-\sqrt{6}\right)x+\sqrt{6}\left(-\sqrt{6}\right)[/tex]
=x^2-6
iii)[tex]x^2-\left(\frac{4}{5}+\frac{5}{4}\right)x+\frac{4}{5}\cdot \frac{5}{4}[/tex] (inverse of another zero)
=[tex]x^2-\frac{41x}{20}+1\\[/tex]
iv)[tex]x^2-\left(3-\sqrt{2}+3+\sqrt{2}\right)x+3-\sqrt{2}\cdot \:3+\sqrt{2}[/tex]
=[tex]x^2-6x+3-2\sqrt{2}[/tex]
Step-by-step explanation: