please solve this question........
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Given:
(x+1/x)=16
[tex] squaring \: both \: side\\ \\ \implies(x + \frac{1}{x})^{2} = {(16)}^{2} \\ \\ \implies ( {x}^{2} + \frac{1}{ {x}^{2} } + 2x \frac{1}{x}) = (16)^{2} \\ \\ \implies {x}^{2} + \frac{1}{ {x}^{2}} + 2 = ( {16)}^{2} \\ \\ \implies {x}^{2} + \frac{1}{ {x}^{2} } = {(16)}^{2} - 2 \\ \\ \implies {x}^{2} + \frac{1}{ {x}^{2} } = 256 - 2 \\ \\ \implies {x}^{2} + \frac{1}{ {x}^{2} } = 254[/tex]