please solve this question it's very important
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please solve this question it's very important
I will mark it brainliest answer
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[tex]\sf{\large{\underline{\boxed{\pink{\mathsf{♡ ANSWER ♡}}}}}}[/tex]
[tex]\green{\large\underline{\underline\mathtt{Given :}}}[/tex] AB =AC & BE is perpendicular to AC.
[tex]\red{\large\underline{\underline\mathtt{Required to prove :}}}[/tex] BC^2 = 2AC.CE
[tex]\sf{\underline{\boxed{\green{\large{\bold{ SOLUTION}}}}}}[/tex]⠀⠀⠀⠀
BE^2 = BC^2 +EC^2 ----1
BE^2 =AB^2 +AE ^2 -----2
BC^2+EC^2 =AB^2+AE^2
BC^2 = AC^2 +AE^2-EC^2
=AC^2 +(AE+EC) (AE-EC)
=AC[AC+AE-EC]
HENCE,
[tex]{\boxed{BC^2 = 2AC.CE}}[/tex]
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