please solve this question
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please solve this question
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ANSWER
Join DC with AE.
As we know in parallel lines with a joining transversal line, the corresponding angles are equal.
Let The meeting point of DC and AE be K.
Thus, angle BAE=angle CKE
In triangle KCE, sum of angles will always be 180°
So, angle CKE+angle CEK+angle ECK=180°
110°+25°+(180-x)°=180°
x=110°+25°
x=135°