please solve this with showing all the workings
Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their present ages.
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please solve this with showing all the workings
Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their present ages.
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Answer:
dilip age is 38 and his son age is 14
Step-by-step explanation:
two year ago....
dilip age= 3×(dilip's son)..........eq1
two year hence....
2×(dilip age= 5×(dilip's son)...............eq2
let's dilip son present age is x
then by first condition two year ago
dilip age =( x-2) ×3 = 3x - 6
dilip age in present is 3x-4
dilip age two year hence 3x-2
dilip son age two year hence is x+2
by ...........eq2
2(3x-2) = 5(x+2)
6x-4=5x+10
6x-5x= 10+4
x=14
dilip son age in present is 14
dilip age in present is = 3x-4 = 42-4= 38
Answer:
let,
dilip age was=x
his sone age=y
from the question,
3(x-2)=y-2 eq1,