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© Is the answer
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Reason:-
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=> The difference between any two IP's is much more when the configuration behaves as noble gas.
=> In option a(❌) ,
The configuration is already a noble gas configuration so it's IP is much higher than the gap between 2nd and 3rd IP
=> In option b(❌) ,
After the removal of 1st electron, it attains the noble gas configuration... So, the difference between 1st and 2nd IP is much higher than 2nd and 3rd IP.
=> In option c(✔️) ,
After the removal of 2 electrons, it attains the noble gas configuration... So, the difference between 2nd and 3rd IP is much higher than 1st and 2nd..
The required terms as per given ⬆️
=> In option d(❌) ,
After removal of 1 electron, the s orbital is fully filled and thus the difference in 1st and 2nd IP is higher than 2nd and 3rd IP.
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Answer:
the answer is d
Explanation: