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Tangents drawn from an external point to a circle are equal in length.
So, BF=BD=6cm
CD=CE=8cm
AF=AE= x (let)
Clearly,
ar(ABC)=ar (AOC)+ar (BOC)+ar (AOB)
63cm^2=1/2× 8 × (x+3)+1/2×14×2+1/2 × (6+x)× 3
63= 24+3x /2 + 42 + 18+3x/2
63×2= 3x+3x+24+18
126= 6x+84
6x= 42
x= 7
So, AB=(x+6)=13cm
I think it may help u.