please tell me in python language
it's urgent
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please tell me in python language
it's urgent
please
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Explanation:
The time taken is 73.5 months.
Step-by-step explanation:
Given : Meena has a recurring deposit of RS.340 per month at 6% per annum. If she gets RS.7157 at the time of maturity.
To Find : The total time for which the account was held ?
Solution :
Using the formula,
MV=Pn+P(\frac{n(n+1)}{2})\times \frac{r}{12\times 100}
Where,
P = Rs.340 is the principal
r = 6% p.a. is the rate of interest
MV = Rs. 7157 is the maturity value
n is the time taken.
Substitute the values,
7157=340n+340(\frac{n(n+1)}{2})\times \frac{6}{12\times 100}7157=340n+340(
2
n(n+1)
)×
12×100
6
7157=340n+170n(n+1)\times 0.0057157=340n+170n(n+1)×0.005
7157=340n+0.85n(n+1)7157=340n+0.85n(n+1)
On solving further,
n^2+41n-8420=0n
2
+41n−8420=0
Solve by quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}x=
2a
−b±
b
2
−4ac
n=\frac{-41\pm\sqrt{41^2-4(1)(-8420)}}{2(1)}n=
2(1)
−41±
41
2
−4(1)(−8420)
n=\frac{-41\pm 188}{2}n=
2
−41±188
n=\frac{-41+188}{2},\frac{-41-188}{2}n=
2
−41+188
,
2
−41−188
n=73.5,-114.5n=73.5,−114.5
Reject n=-114.5.[/tex]
The time taken is 73.5 months.