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Answer:
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Given :- PA=10cm , PQ=14cm, RB=8cm
To find PS =
We have PA⊥SRand PQ=14
∵ PQ=SR{Opposite sides ofparallelogram}
∵ SR=14cm
PA⊥SR
Now, area of parallelogram PQRS= SR×PA = (14×10)cm^2= 140cm^2
RB⊥PD
area of parallelogram PQRS=PS×RB
140 =PS×8
140/8 = PS
17.5 cm = PS