pls anyone find the solution
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Now ,
let y = 3^logx
Taking log on both sides, we have,
logy = log(3^logx)
logy = (logx)(log3)----------( 1 )
Also let z = x^log3
Again taking log on both sides, we
have,
logz = log(x^log3)
logz = (log3)(logx)--------( 2 )
From --------( 1 ) &------( 2 )
we have logy=logz.
Hence, y = z,that means
3^(logx)=x^(log3)------------( 3 )
So, 3^logx + x^log3 = 54
3^logx + 3^logx = 54
from ----------( 3 )
2*(3^logx) = 54
3^logx = 54/2 = 27
3^logx = 27
3^logx = (3³)
3^logx = 3^3
logx = 3