And how many moles of Mg3(PO4)2 will contain 0.25 moles of oxygen atoms?
Update:its even enough if u cud giv the eq alone....its urgent
And how many moles of Mg3(PO4)2 will contain 0.25 moles of oxygen atoms?
Update:its even enough if u cud giv the eq alone....its urgent
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Verified answer
Mg3(PO4)2 <----> 3 Mg2+ + 2 PO43-
1 mole contains 4 x 2 = 8 moles of oxigen atoms
0.25 / 8 = 0.031 moles Mg3(PO4)2
Mg3(PO4)2-------->3Mg+2 +2PO4-3
1 mole of Mg3(PO4)2 contains 8 moles of oxygen atoms
so 0.25 moles of oxygen atoms are present in 1/32 =0.03125 moles of Mg3(PO4)2