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Given : (complete Question is )
The areas allotted for a hockey court and a shooting range of NCC TRAINING CAMP
The shapes of the hockey court and the shooting range are square and triangle respectively. Both of the courts have a common vertex that coincide with the centre of circular camp. The construction of the shooting range is such that the angle to centre is 90°. The radius of the circular camp is 180 metres.
To Find :
1) What is the area allotted to shooting range ?
(a) 12, 600 m² (b) 22, 000 m² (c) 16,200 m² (d) 16, 880 m²
2) What is the area allotted to hockey court ?
(a) 12, 600 m² (b) 22, 000 m² (c) 20, 000 m² (d) 16, 200 m²
3) What is the area of training camp.
(a) 101736 m² (b) 32400 m² (c) 16200 m² (d) 20000 m²
4) If the management of NCC TRAINING Camp likes to allot space for some more sports, how much area is available to them?
(a) 85, 536 m² (b) 95, 800 m² (c) 60, 040 m² (d) 69,336 m²
Solution :
OA = OB = Radius = 180 m
angle = 90°
Area of shooting range = (1/2) * 180 * 180 = 16200 m²
OD = Radius = 180 m
OE = 180/√2 = 90√2 m
Area of Hockey court = (90√2)² = 16200 m²
area of training camp. = π(180)² = 3.14(180)² = 1,01,736 m²
area is available = 1,01,736 - 16200 - 16200 = 69,336 m²
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