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Step-by-step explanation:
Q.7 ) Let the two digit number be 10x+y
Given that the sum of the digits is 9
x+y=9------------------(1))
Given that the number obtained by interchanging the digits exceeds the given number by 27
10y+x=10x+y+27
9x−9y=−27
taking 9 as common
x−y=−3---------------------(2)
Adding equation 1 and 2
x+y=9
x−y=−3
2x=6
x=3
3+y=9
y=6
The number is 10x+y is 36.