pls help it's urgent...
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Answer:
Given:
Explanation:
[tex]\rule{300}{1.5}[/tex]
From the formula of linear expansion we know that,
[tex]\bigstar\;\underline{\boxed{\sf \Delta L=L_{o}\;\alpha\;\Delta T}}[/tex]
Here,
Solving & Substituting the values,
[tex]\longrightarrow\sf \Delta L=L_{o}\;\alpha\;\bigg(T-T_{o}\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times \bigg(37-25\bigg)\\\\\\\\\longrightarrow\sf \Delta L=20\times \bigg(8.5\times 10^{-6}\bigg)\times 12\\\\\\\\\longrightarrow\sf \Delta L=240\times 8.5\times 10^{-12}\\\\\\\\\longrightarrow\sf \Delta L=2040\times 10^{-6}\\\\\\\\\longrightarrow\sf \Delta L=2.04\times 10^{-3}\\\\\\\\\longrightarrow\large{\underline{\boxed{\red{\sf \Delta L=2.04\times 10^{-3}\;cm}}}}[/tex]
∴ The Titanium plate will expand by 2.04 × 10⁻³ cm.
[tex]\rule{300}{1.5}[/tex]
Answer:
2.04×10-3
Explanation:
is the correct answer