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Answer
Given:−
Find:−
Area of the given figure.
Solution:−
In ∆CDR
=> Area of△CDR= 21 ×base×height
=> Area of△CDR= 21×40×30
=> Area of△CDR= 21 ×1200
=> Area of△CDR= 21200
=> Area of△CDR=600m²
=> ∴ar(CDR)=600m²
In ∆DQE
=> Area of△DQE= 21 ×base×height
=> Area of△DQE= 21 ×50×30
=> Area of△DQE= 21 ×1500
=> Area of△DQE= 21500
=> Area of△DQE=750m²
=> ∴ar(DQE)=750m²
In ∆EQA
=>Area of△EQA= 21 ×base×height
=> Area of△EQA= 21 ×30×50
=> Area of△EQA= 21 ×1500
=> Area of△EQA= 21500
=> Area of△EQA=750m²
=> ∴ar(EQA)=750m²
In ∆ABP
=> Area of△ABP= 21 ×base×height
=> Area of△ABP= 21 ×30×20
=> Area of△ABP= 21 ×50
=> Area of△ABP= 2600
=> Area of△ABP=300m²
=> ∴ar(ABP)=300m²
In Trapezium PBCR
=> Area of PBCR= 21 ×(a+b)×h
=> Area of PBCR= 21 ×(20+40)×40
=> Area of PBCR= 21 ×(60)×40
=> Area of PBCR= 21 ×60×40
=> Area of PBCR= 21 ×2400
=> Area of PBCR= 22400
=> Area of PBCR=1200m²
=>∴ar(PBCR)=1200m²
➡Area of the field = ar(CDR) + ar(DQE) + ar(EQA) + ar(ABP) + ar(PBCR)
➡Area of the field = 600 + 750 + 750 + 300 + 1200
➡Area of the field = 3600m².
Hence,
Area of the given field is 3600m².