PLS SOLVE AND HELPPPPPPPPP
PLS PLS PLS
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PLS SOLVE AND HELPPPPPPPPP
PLS PLS PLS
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Step-by-step explanation:
If tan theta = 3/4, then what is the value of sin theta and sec theta?
Let theta = x
tan x=3/4. , sin x=? and. sec x=?
sec^2x=1+tan^2x=1+9/16= 25/16
sec x=+/-(5/4). Answer
cos x= +/- 4/5
sin x=+/-√(1-cos^2x) = +/- √(1–16/25)=+/- √(9/25) = +/-3/5. Answer.
Second-method:-
tan x= 3/4
or. sin x/cos x= 3/4
or. (sin x)/3= (cos x)/4 =k(led)
or. sin x= 3k. , cos x=4k
sin^2x+cos^2x=1. =>. 9k^2+16k^2=1. or. 25k^2 = 1
k = +/-1/5
sin x= 3k = +/-3/5. Answer
and. cos x=4k = +/-(4/5). or sec x= +/-(5/4). Answer.