pls solve this maths question
(9 or 10 or both) its upto ur ability
Share
pls solve this maths question
(9 or 10 or both) its upto ur ability
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Answer:
9.
[tex]for \: real \: roots \\ d > 0 \\ {b}^{2} - 4ac > 0 \\ {k}^{2} - 4 \times 1 \times - 4 > 0 \\ {k}^{2} + 16 > 0 \\ {k}^{2} > - 16 \\ k > \sqrt{ - 16} [/tex]
10.
[tex]for \: real \: roots \\ d > 0 \\ {b}^{2} - 4ac > 0 \\ { - 2}^{2} - 4 \times k \times k > 0 \\ 4 - 4 {k}^{2} > 0 \\ - 4 {k}^{2} > - 4 \\ {k}^{2} > \frac{ - 4}{ - 4} \\ {k}^{2} > 1 \\ k > \sqrt{1} \\ k > + 1 \: or - 1[/tex]
Hope this helps you...
Be Brainly!!!
Answer:
1) - root 16
2) + or - 1
hope it helps