pls solve this question
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Comparing with std equation
ax^2 + bx + c
We get,
a=k
b=2
c=3k
Sum of roots = -b/a = -2/k
Product of roots = c/a= 3
ATQ:
-2/k=3
Therefore, k=-2/3
here is your answer !!!
a = K
b = 2
c = 3k
let the zeroes of polynomial be
=> -2 / k --------------------(1)
product =
c/a
=> 3k / k
now ,
sum is equal to PRODUCT
we get
3 = -2 / k
k = > -2 / 3
hope it helps you dear !!!
thanks !!!