Pls solve this question with all the steps
Share
Pls solve this question with all the steps
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Step-by-step explanation:
From figure:
In ΔAOB & ΔCOB,
OA = OC
AB = BC {Since ABCD is a rhombus}
OB = OB
∴ ΔAOB ≅ ΔCOB
⇒ ∠AOB = ∠BOC ----- (i)
∴ ΔAOD ≅ ΔCOD
⇒ ∠AOD = ∠COD ----- (ii)
Now,
⇒ ∠AOB + ∠BOC + ∠COD + ∠AOD = 360°
⇒ ∠BOC + ∠BOC + ∠COD + ∠COD = 360° {From (i),(ii)}
⇒ 2∠BOC + 2∠COD = 360°
⇒ ∠BOC + ∠COD = 360°/2
⇒ ∠BOC + ∠COD = 180°
⇒ ∠DOB = 180°
Therefore, DOB is a straight line.
Hope it helps!