pls tell this question fast
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
In △ABD,
∠BAD+∠ADB+∠B=180°
∠BAD+90° +∠B=180°
∠BAD=90° −∠B ......(1)
In △ABC,
∠A+∠B+∠C=180 °
∠B+∠C=90°
∠C=90° −∠B
∠ACB=90° −∠B .......(2)
From 1 and 2, we get,
∠BAD=∠ACB
Hence proved.
Step-by-step explanation:
GIVEN THAT:-
ABC IS A RIGHT ANGLE TRIANGLE
AD PERPENDICULAR TO BC
PROVE THAT:-
Angle BAD= Angle ACB
Triangal BAD = Triangle ACD (both are right angle) - - - (1)
Therefore
Angle DAC = Angle ABD
Angle CDA = Angle ADB
Therefore angle BAD = Angle ACB
PROVE!