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Answer:
PbN2O6 & Compound is Pb(NO3)2 (lead nitrate)
Explanation:
Given,
mass percentage
Pb = 62.54%
N = 8.46%
O = 29%
Molecular Weight
Pb = 207g/mol
N = 14g/mol
O = 16g/mol
we need to find out the total mass of compound,
molecular weight/x = mass percentage/100
Let's Find Out,
for lead (Pb)
207/x = 62.54/100 (since it is percentage)
x = 207/0.6254
x = 330.988
similarly for Nitrogen (N)
14/x = 8.46/100
x = 14/0.0846
x = 165.48
similarly for Oxygen (O)
16/x = 29/100
x = 16/0.29
x = 55.17
now,
which is highest among the above?
330.988>165.48>55.17
so,
which is highest will be 1, so lead is 1 (Pb)
now, to find number of Atoms for Nitrogen,
N = Pb/N
N = 330.988/165.48
N = 2
for Oxygen,
O = 330.988/55.17
O = 6
so, empirical formula will be,
PbN2O6
and Compound is,
Pb(NO3)2