plz ans the ques( attached)
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plz ans the ques( attached)
plz don't spam
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Solution:- ∫ (1+sinx)dx
=> ∫√(1+sinx)×(1-sinx)/(1-sinx)dx
=>∫√ (1-sin²x)/(1-sinx)dx
=>∫√ (cos²x)dx/(1-sinx)
=>∫ cosx/√(1-sinx)____(1)
let (1-sinx) =t
d(1-sinx)/dt =dt/dt
=> -cosxdx=dt
From (1)
=> ∫-dt/√t from limit 0 to π/2 from given quest
=>[ -(t½)/1/2 ]₀ᵖⁱˡ²
=>put the value of t = 1-sinx
=>-2[(1-sinx)]₀ᵖⁱˡ²
=>-2[{1-sinπ/2}-{1-sin0}]
=>-2[(0)-1]
=> 2 Answer
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Answer:
refer to this attachment ✅✅