plz answer fast ....... irrelevant answers will be reported and if ur answer is right I will follow u and like ur answers and mark u as brainilist.....plz answer step by step
Share
plz answer fast ....... irrelevant answers will be reported and if ur answer is right I will follow u and like ur answers and mark u as brainilist.....plz answer step by step
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
pls mark brainliest follow me her is your answer
Step-by-step explanation:
Given : OO is the centre of the circle.
Seg ABAB is a diameter, CDCD is the tangent at CC.
BDBD is a tangent at BB
In ΔCODΔCOD and ΔBODΔBOD
⇒OC=OB⇒OC=OB ....(Radii of same circle)
⇒CD=DB⇒CD=DB ....(Tangent from an external point)
⇒OD=OD⇒OD=OD ....(Common side)
⇒ΔCOD=ΔBOD⇒ΔCOD=ΔBOD (SSS test)
⇒ΔCOD=ΔBOD=x⇒ΔCOD=ΔBOD=x (c.a.s.t.) equation (i)
In ΔAOCΔAOC, AO=OCAO=OC ....(Radii of same circle)
⇒⇒ ∠OAC=∠OCA=y∠OAC=∠OCA=y ....(Isoceles ΔΔ theorem) equation (ii)
⇒∠COB=∠OAC+∠OCA⇒∠COB=∠OAC+∠OCA ....(Remote interior ∠∠ theorem)
⇒∠COD+∠BOD=∠OAC+∠OCA⇒∠COD+∠BOD=∠OAC+∠OCA
⇒x+x=y+y⇒x+x=y+y ....[From equation (i) and (ii)]
⇒2x=2y⇒2x=2y
⇒x=y⇒x=y ....(dividing by 22)
⇒∠COD=∠OCA⇒∠COD=∠OCA
⇒⇒ Seg OD∥OD∥ chord ACAC. ....(Alternate ∠s∠s test)
Hence, proved.