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Answer:
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Step-by-step explanation:
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Verified answer
Given
Cosec θ =10/8
We know that Cosec θ = Hypotenuse/Perpendicular
Construction
Construct a Δ ABC
In which
AC = Hypotenuse = 10 units
AB= Perpendicular = 8 Units
BC= Base
For diagram refer to attachment given below
Solution
We know that Cosec θ = Hypotenuse/Perpendicular
Form ΔABC ; ∠ABC= 9
By Pythagoras theorem
BC² +AB²=AC²
BC²=AB² - BC²
BC²=10²-8²=100-64=36
BC²=36
BC = √36=6
Base = BC= 6 units
We know that
Sec θ = Hypotenuse /Base = AC/BC=10/6
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