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Answer:
Solve equation [2] for the variable x
[2] 2x = 5y + 15
[2] x = 5y/2 + 15/2
// Plug this in for variable x in equation [1]
[1] 3•(5y/2+15/2) + 5y = 10
[1] 25y/2 = -25/2
[1] 25y = -25
// Solve equation [1] for the variable y
[1] 25y = - 25
[1] y = - 1
// By now we know this much :
x = 5y/2+15/2
y = -1
// Use the y value to solve for x
x = (5/2)(-1)+15/2 = 5
Answer:
[tex]\frac{30(2x-5y)}{x}[/tex]
Step-by-step explanation:
[tex]=10\left(2x+5y\right)\frac{3}{x}[/tex]
=[tex]\frac{3X10(2x+5y)}{x}[/tex]
=[tex]\frac{30\left(2x+5y\right)}{x}[/tex]
Hope this helps you