plz bro solve this question ....
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Answer
6 ± √10
Explanation
Let, x - 1 = a
x - 3 = b
Then, x - 1 - 1 = a - 1
→ x - 2 = a - 1
And, x - 3 - 1 = b - 1
→ x - 4 = b - 1
Now,
Put value of (x - 1), (x - 2), (x - 3), (x - 4) in terms of a and b
Take LCM
This gives
Now cross multiply
→ 6ab - 3a - 3b = 7ab - 7a - 7b + 7
→ 7a + 7b - 3a - 3b = 7ab - 6ab + 7
→ 4(a + b) = ab + 7
Now put a as (x - 1) and b as (x - 3)
→ 4(x - 1 + x - 3) = (x - 1)(x - 3) + 7
→ 4(2x - 4) = (x² - x - 3x + 3) + 7
→ 8x - 16 = x² - 4x + 3 + 7
→ x² - 4x - 8x + 10 + 16 = 0
→ x² - 12x + 26 = 0
Now solve it using quadratic equation