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Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number.
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Answer:
29,31
Step-by-step explanation:
Let x be one odd the number.The consecutive odd number would be x+2.
Sum of the larger number and twice the smaller number is 27 less than four times the smaller number
=> x+2 + 2(x) +27 = 4x
3x + 29 = 4x
x = 29.
Thus the larger number is 29 + 2 = 31
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