plz SOLVE ..... its urgent .... IT'S FROM CHAPTER-TRIANGLES OF CLASS 9
it's question 4 from ex.- 7.4
plzz. .... . . . I have test tomorrow ☺
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plz SOLVE ..... its urgent .... IT'S FROM CHAPTER-TRIANGLES OF CLASS 9
it's question 4 from ex.- 7.4
plzz. .... . . . I have test tomorrow ☺
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the second image is to prove angle B > angleD
4. AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD
(See figure). Show that A > C and B > D.
Ans. Given: ABCD is a quadrilateral with AB as smallest and CD as longest side.
To prove: (i) A > C (ii) B > D
Construction: Join AC and BD. ( figure is in the pic )
Proof: (i) In ABC, AB is the smallest side.
.: < 4 < 2 ……….(i)
[Angle opposite to smaller side is smaller]
In ADC, DC is the longest side.
3 < 1 ……….(ii)
[Angle opposite to smaller side is smaller]
Adding eq. (i) and (ii),
4 + 3 < 1 + 2
C < A
=> A > C
(ii) In ABD, AB is the smallest side.
5 < 8 ……….(iii)
[Angle opposite to smaller side is smaller]
In BDC, DC is the longest side.
6 < 7 ……….(iv)
[Angle opposite to smaller side is smaller]
Adding eq. (iii) and (iv),
5 + 6 < 7 + 8
< D < B
=> B > D
hope this helps you ##