Plz solve ques no 6 any one
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in ΔQTR,
∠TRS is exterior angle ∴∠QTR+∠TQR=∠TRS
∠QTR=∠TRS-TQR.............................equation 1
in ΔPQR,
∠PRS is exterior angle ∴∠QPR+∠PQR=∠PRS
∠QPR+2∠TQR=2∠TRS (QT and RT are angle bisectors)
∠QPR=2∠TRS-2∠TQR
∠QPR=2(∠TRS-∠TQR) (taking 2 common)
from equation 1
∠QPR=2(∠QTR)
∠QTR=1/2∠QPR
hence proved
hope this helps