plz solve this my boards are coming
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hey mate!!!
Ur answer!!
2)
Sol: Given quadratic equation is ax2+ bx - 6 = 0. If x = 3 /4 is root of the equation then a(3/4)2 + b(3/4) - 6 = 0 ⇒ (9a / 16) + (3b / 4) - 6 = 0 ⇒ 9a + 12b - 96 = 0 ⇒ 3a + 4b - 32 = 0 ---------(1) And x = -2 is root of the equation then a(-2)2 + b(-2) - 6 = 0 ⇒ 4a - 2b - 6 = 0 ---------(2) Solving (1) and (2) we get a = 4 and b = 5.