plz solve this question for me
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Answer:
we can find this by using distance formula:-
i.e, d^2=(x2-x1)^2 + (y2-y1)^2
first for points (x, y) and (3, 6)
d^2=(3-x)^2 +(6-y)^2.......(1)
now for (x, y) and (-3, 4)
d^2=(-3-x)^2+(4-y)^2 .....(2)
equating eqn 1 and 2 we get
(3-x)^2 + (6-y)^2= (-3-x)^2 +(4-y)^2 =9+x^2- 6x +36+y^2-12y=9+x^2+6x+16+y^2-8y
=-6x+36-12y=6x+16-8y...(after cancellation)
now bringing similiar terms together
-6x-6x-12y+8y= 16-36
-12x-4y=-20
12x+4y=20
3x+y=5
hope it helps ......
Answer:
9y-x-10 = 0
or x-9y+10 = 0
Step-by-step explanation:
distance between two points (a,b) & (c,d)is given as:
according to question
point (x,y) is equidistant from (3,6) &(-3,4)
refer attachment...
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