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Explanation:
Net force on the system of masses given above is given as
F = 60N
Now as per Newton's second law we have
F = ( m1 + m2 + m3 ) a
60= ( 6+4+2)× a
a= 60 / 12 = 5m/s^2
Now tension at the point A is given by Newton's law
F = ma
Fa = ( 4+2)×5 = 30N
similarly we have to find tension at point B
Fb = ( 4+1) × 5
= 25 N
similarly we have to find tension at point C
Fc = 4× 5 = 20N
Now as per above the tension at Point A ,B,C is 30N , 25N ,20N
hope it helps you