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electronic configuration of Zn is [Ar] 3d10 4s2
=unpaired electrons is 0
electronic configuration of Fe2+ is [Ar]3d6 4s2
as removing of electrons and adding of electrons takes place in the 4s shell so therefore electronic configuration of fe2+ is [Ar]3d6, unpaired electrons =4
electronic configuration of Ni3+is [Ar] 3d7, unpaired elctrons =3
electronic configuration of Cu+ is [Ar] 4s1 3d9 unpaired elctrons =1
therefore maximum number of unpaired d electrons is in Fe2+ as it is having 4 un'aired electrons....
Hope it helped