Plzz answer my questions
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
★Answer★ ☝️☝️
Thus, ∠GOA = ∠GOE + ∠ EOA = 30∘ + 60∘ = 90∘.
★Justification★:
Justification:
(i)Join BC.
Then, OC = OB = BC triangle. (By construction)
∴ ∠COB is an equilateral triangle.
∴ ∠COB = 60∘.
∴ ∠EOA = 60∘.
(ii)Join CD.
Then, OD = OC = CD (By construction)
∆DOC is an equilateral triangle.
∴ ∠DOC = 60∘.
∴ ∠ FOE = 60∘.
(iii)Join CG and DG.
In ΔODG and ΔOCG,
OD = OC[ Radii of the same arc]
DG=CG [Arcs of equal radii]
OG=OG [Common]
∴ Δ ODG = ΔOCG [SSS Rule]
∴ ∠ DOG= ∠COG [CPCT]
∴ ∠FOG = ∠ EOG = 1/2 ∠FOE = 1/2 (60∘) = 30∘
Thus, ∠GOA = ∠GOE + ∠EOA = 30∘ + 60∘ = 90∘
∴ ∠AOJ= ∠GOJ= 1/2 ∠GOA = ½(90°)=45
*Hope it helps you!
Be Brainly .
★ ★ ★ ★ ★