p(m)=m²-3m+ 1, find the value of p(1) and p(-1).
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Answer:
p(E2)=2mn(2m−1)n
Step-by-step explanation:
Let A={a1,a2,...an}
Let S be the sample space and E1 be the event that Pi∩Pj=ϕ for i=j
and E2 be the event that P1∩P2∩...∩Pm=ϕ
Therefore numbers of subsets of A=2n
Therefore each P1,P2,...Pm can be selected in 2n ways
∴n(S)= total number of selection of P1,P2,...Pm=(2n)m=2nm
When P1∩P2∩...∩Pm=ϕ
i.e elements of A does not belong to all the subsets.
There are 2m ways on element does not belong to a subset,
on the other hand, there is only one way the elements can belong to the intersection.
Therefore (2m−1) elements does not belong to the intersection.
n(E
thanks me later!!! labyaaa<♡
Verified answer
Answer:
I)-1
II)5
Step-by-step explanation:
p(m)=m²-3m+ 1
p(1)=1²-3(1)+1
=1-3+1
=-1
p(-1)=-1²-3(-1)+1
=1+3+1
=5
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