PQR is a triangle, right-angled at Q. If ∠PRQ = θ, side PQ = 3 units and side QR = 1 unit, find the
value of sin2
θ + cos2
θ.
please answer this question yesterday also I asked but someone answered wrong...please someone answer
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PQR is a triangle, right-angled at Q. If ∠PRQ = θ, side PQ = 3 units and side QR = 1 unit, find the
value of sin2
θ + cos2
θ.
please answer this question yesterday also I asked but someone answered wrong...please someone answer
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Answer:
Given, PR+QR=25 .....(i)
Also PQ=5
By Pythagoras Theorem,we get,
PR
2
=PQ
2
+QR
2
⇒PR
2
=25+QR
2
⇒PR
2
−QR
2
=25
⇒(PR+QR)(PR−QR)=25
⇒25(PR−QR)=25 .....(from (i))
⇒PR−QR=1 ......(iii)
Adding equation (i) and (iii), we get
PR+QR=25 (i)
PR−QR=1
2PR=26
⇒PR=
2
26
⇒PR=13
Therefore, QR=25−PR
=25−13
=12
sinP=
PR
QR
=
13
12
cosP=
PR
PQ
=
13
5
tanP=
PQ
QR
=
5
12
Step-by-step explanation:
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Answer:
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