present ages?
19) A father is 7 times as old as his son. Two years ago, the father was 13 times as old
as his son. What are their present ages?
Share
present ages?
19) A father is 7 times as old as his son. Two years ago, the father was 13 times as old
as his son. What are their present ages?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Answer:
Step-by-step explanation:
Answer:
There is two answer which would you luke please mark me Brainliest.
1)
Let the present age of the son be x and that
to of his father which is 7 times =7x
Then, 2 years ago their ages :
(x-2) of son
(7x-2) of father
Given, 13(x−2)=7x−2
Then,
13x−26=7x−2
=13x−7x=26−2
6x=24
or x=4 and that of his father = 28 years
age of son=x=4years
age of father=7x=28years
Step-by-step explanation:
2)
son’s age = 4 yrs
father’s age = 28 yrs , both current.
sol : let son’s present age = x , then father’s current age = 7x;
then two years ago , son’s age = x - 2 and
father’s age = 7x - 2
now according to question, two years ago father’s age was 13 times of his son
therefore
7x - 2 = 13(x - 2)
this on solving gives
x = 4 that is son’s age
and father’s age = 7x = 28 years old.