Product of two consecutive integer is divisible by (a) 2 (b) 3 (c) 5 (d) 7
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Product of two consecutive integer is divisible by (a) 2 (b) 3 (c) 5 (d) 7
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Answer:
Let the 2 consecutive numbers be, x,x+1
product of these consecutive numbers, =x(x+1)
(1) even
let, x=2k
product =2k[2k+1]
from above equation it is clear that the product is divisible by 2
(2) odd
let, x=2k+1
product =(2k+1)[(2k+1)+1]
=2(2k
2
+3k+1)
from above equation it is clear that the product is divisible by 2
Step-by-step explanation:
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