prove that (21)^n is an odd number for any natural number number
Share
prove that (21)^n is an odd number for any natural number number
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
(21)^n
Let us check for n=1
(21)^1= 21 which is odd..
Let us now check for 2
(21)^2=441
.
.
.
.
Similarly check for more 2 to 3 natural numbers and state that it is true for all value of n where n belongs to natural no.
Hope it helped ......
Pls mark as brainleist...........
Answer:
21 is an odd number and by the fundamental theorem of arithmetic it multiplied by itself would give only higher exponents of 3 and 7. As 2 is not its prime factor therefore any exponent of it cannot be an even number .