Prove that a chord of the length equals to the radis subtainds an angle of 60° at the centre of a circle.
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Prove that a chord of the length equals to the radis subtainds an angle of 60° at the centre of a circle.
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Question:
Prove that a chord of the length equals to the radis subtainds an angle of 60° at the centre of a circle.
Step-by-step explanation:
Let the chord be 8cm and and angle 60 degree given
A chord of 8 cms long subtends 60 degree angle at the center, then the Largest Chord i.e the Diameter, as we know makes 180 degree angle at the Center, here the length of that Chord will be 180/60 x 8 =…. As under....
180/60 x 8 cms = 3 x 8 = 24 cms. Then the radius ( radius is half of the Diameter or twice the length of radius) will be… 24/2….
Radius is 12 cms. Answer.
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Hence proved