prove that a cyclic rhombus is a square
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prove that a cyclic rhombus is a square
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Step-by-step explanation:
In Figure ABCD is Rhombus in circles
Isliya angle A+ angle C and Angle B+ Angle D. ( opposite angle of Rhombus Is Equal )
Angle A+ Angle C =180° ( opposite angle of cyclic Rhombus)
isliya Angle A+ Angle A = 180°
Angle A = 90°
And angle B + angle D = 180°. ( Opposite angle Of Cyclic Rhombus)
isliya Angle B+ Angle B = 180°
Angle B = 90°
isliya Angle A = Angle B = Angle C = Angle D = 90°
All angle of Rhombus is right angles then this is a square
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Answer:
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Step-by-step explanation:
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