prove that quadrilateral formed by joining the mid point of all sides of a quadrilateral is a parallelogram
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prove that quadrilateral formed by joining the mid point of all sides of a quadrilateral is a parallelogram
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Answer:
Step-by-step explanation:
Let P,Q,R,S be respectively the midpoints of the sides AB, BC, CD, DA of quad. ABCD and let PQRS be formed by joining the midpoints.
Now, join AC.
In triangle ABC, P and Q are midpoints of AB and BC respectively.
So by mid point theorem,
PQ ll AC and PQ = 1/2 AC.
Now,
In triangle DAC, S and R are midpoints of AD and DC respectively.
Therefore, SR ll AC and SR = 1/2 AC.
Thus, PQ ll SR and PQ = SR.
Hence, PQRS is a ll gm.
Now, join AR which divides triangle ACD into two equal area.
∴ar ( AED ) = 1/2 ar ( ACD ) .. ( 1 )
Median RS divides triangle ARD into two triangle of equal area.
Hence, ar ( DSR ) = 1/2 ( ARD ) .. ( 2 )
From ( 1 ) and ( 2 ), we get : ar ( DSR ) = 1/4 ( ACD ).
Similarly, ar ( BQP ) = 1/4 ( ABC ).
Now, ar ( DSR ) + ar ( BQP ) = 1/4 [ ar ( ACD ) + ar ( ABC )]
Therefore, ar ( DSR ) + ar ( BQP ) = 1/4 [ quad. ABCD] ......... ( 3 )
Similarly, ar ( CRQ ) + ar ( ASP ) = 1/4 ( quad. ABCD ) ......... ( 4 )
Adding ( 3 ) and ( 4 ) , we get
ar ( DSR ) + ar ( BQP ) + ar ( CRQ ) + ar ( ASP ) = 1/2 ( quad. ABCD ) ............... ( 5 )
But, ar ( DSR ) + ar ( BQP ) + ar ( CRQ ) + ar ( ASP ) + ar ( llgm PQRS ) = ar ( quad. ABCD ) .... ( 6 )
Subtracting ( 5 ) from ( 6 ) , we get
ar ( llgm PQRS ) = 1/2 ar ( quad. ABCD ).
Mark it as brainlist
Thnx